# How do you factor 3x^2+6x+x+2?

Apr 26, 2017

$\left(x + 2\right) \left(3 x + 1\right)$

#### Explanation:

Your immediate question should be: why have they chosen this format for the question?

Notice that they split the terms. So does this imply a repeat of some form?

Notice that for $3 {x}^{2} + 6 x \to 3 x \left(x + 2\right)$ and the $x + 2$ is the right hand split part. So we write:

$3 {x}^{2} + 6 x + x + 2 \text{ "->" } \left(3 {x}^{2} + 6 x\right) + \left(x + 2\right)$
$\text{ } 3 x \left(x + 2\right) \textcolor{w h i t e}{. .} + 1 \left(x + 2\right)$

Factor out the $\left(x + 2\right)$ giving

$\text{ } \left(x + 2\right) \left(3 x + 1\right)$