How do you factor #3x^2+8x+4# by using the grouping method?

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Answer 1 · 2018-03-29T02:09:04

#(x + 2)(3x + 2)#

1) Multiply the #a# and #c# terms together which in this case is #3# and #4#.

#3 \times 4 = 12#

2) Find factors of #12# that when added together will get you to the #b# term, which is #8#.

Those two are #2# and #6#.

3) Expand and factor with grouping. Closely follow the steps.

#3x^2 + 2x + 6x + 4#

#x(3x + 2)# and #2(3x + 2)#

#(x + 2)(3x + 2)#