Question

How do you factor `3x^3-x^2-2x`?

Answer 1

`x(3x+2)(x-1)`

Explanation:

First note that every term has `x` in it so the expression can be rewritten as

`x(3x^2-x-2)`

The term in brackets is then a standard quadratic which can be factored as `(3x+2)(x-1)`

So the final expression is `x(3x+2)(x-1)`