# How do you factor 3x^3-x^2-2x?

##### 1 Answer
May 31, 2016

$x \left(3 x + 2\right) \left(x - 1\right)$

#### Explanation:

First note that every term has $x$ in it so the expression can be rewritten as

$x \left(3 {x}^{2} - x - 2\right)$

The term in brackets is then a standard quadratic which can be factored as $\left(3 x + 2\right) \left(x - 1\right)$

So the final expression is $x \left(3 x + 2\right) \left(x - 1\right)$