Question

How do you factor `3yz^2 -4y^2z+6y^3-2z^3`?

Answer 1

It is

`3yz^2 -4y^2z+6y^3-2z^3=3y*(z^2+2y^2)-2z*(2y^2+z^2)=(3y-2z)*(z^2+2y^2)`