How do you factor #4x^2-10x+6#?

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Answer 1 · 2018-06-15T14:51:19

#2(x-1)(2x-3)#

First factor out the GCF by the distributive property:

#4x^2-10x+6#

#2(2x^2-5x+3)#

Now the factors have to have a sum #-5# and a product #2*3=6#

-2, -3 will work

Now factor by grouping, replace the #-5x# with #-2x-3x#

#2(2x^2-5x+3)#

#2(2x^2-2x-3x+3)#

#2(2x(x-1)-3(x-1))#

now factor out #(x-1)#

#2(x-1)(2x-3)#