# How do you factor 4x^3+16x^2+x+4?

$\left(x + 4\right) \left(4 {x}^{2} + 1\right)$
$4 {x}^{3} + 16 {x}^{2} + x + 4$
=$4 {x}^{2} \left(x + 4\right) + \left(x + 4\right)$
=$\left(x + 4\right) \left(4 {x}^{2} + 1\right)$