How do you factor #4x^3-6x^2+2x#?

1 Answer
smendyka
Jun 4, 2017

See a solution process below:

Explanation:

First, we can factor #color(red)(2x)# out of each term in the expression giving;

#(color(red)(2x) * 2x^2) - (color(red)(2x) * 3x) + (color(red)(2x) * 1) =>#

#color(red)(2x)(2x^2 - 3x + 1)#

Next we can factor the quadratic as:

#2x(2x - 1)(x - 1)#

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