# How do you factor 4x^3-8x^2-12x?

Feb 17, 2016

$4 x \left(x + 1\right) \left(x - 3\right)$

#### Explanation:

Since all terms contain at least one $x$ and a multiple of $4$, the GCF $4 x$, which can be factored out.

Rewrite the trinomial.

$4 x \left({x}^{2} - 2 x - 3\right)$

Factor the trinomial. Find two numbers that when added equal $- 2$ and when multiplied equal $- 3$. The numbers $1$ and $- 3$ fit the requirements.

Rewrite the trinomial in its factored form.

$4 x \left(x + 1\right) \left(x - 3\right)$