How do you factor #4x^3-8x^2-12x#?

1 Answer
Feb 17, 2016

Answer:

#4x(x+1)(x-3)#

Explanation:

Since all terms contain at least one #x# and a multiple of #4#, the GCF #4x#, which can be factored out.

Rewrite the trinomial.

#4x(x^2-2x-3)#

Factor the trinomial. Find two numbers that when added equal #-2# and when multiplied equal #-3#. The numbers #1# and #-3# fit the requirements.

Rewrite the trinomial in its factored form.

#4x(x+1)(x-3)#