How do you factor #4x^5 + 6x3 + 6x^2 + 9#?

1 Answer
Apr 16, 2018

Answer:

#(2x^3+3)(2x^2+3)#

Explanation:

Factor by grouping
Put parenthesis around two first and last terms
#(4x^5+6x^3)+(6x^2+9)#
Factor out gcf
#2x^3(2x^2+3)+3(2x^2+3)#
If you did it right the parenthesis should be same so you can cross one out and make a new parenthesis with the two terms you factored out
#(2x^3+3)(2x^2+3)#
This is more concept than logic so don't mind the addition sign in between