# How do you factor 4x^5 + 6x3 + 6x^2 + 9?

Apr 16, 2018

$\left(2 {x}^{3} + 3\right) \left(2 {x}^{2} + 3\right)$

#### Explanation:

Factor by grouping
Put parenthesis around two first and last terms
$\left(4 {x}^{5} + 6 {x}^{3}\right) + \left(6 {x}^{2} + 9\right)$
Factor out gcf
$2 {x}^{3} \left(2 {x}^{2} + 3\right) + 3 \left(2 {x}^{2} + 3\right)$
If you did it right the parenthesis should be same so you can cross one out and make a new parenthesis with the two terms you factored out
$\left(2 {x}^{3} + 3\right) \left(2 {x}^{2} + 3\right)$