How do you factor 4y^2 + 25y + 6?

Mar 3, 2017

Factors of given qudratic equation are : $\left(y + 6\right) \left(4 y + 1\right)$

Explanation:

$4 {y}^{2} + 25 y + 6$

$4 {y}^{2} + 24 y + y + 6$

$\underline{4 {y}^{2} + 24 y} + \underline{y + 6}$

$4 y \left(y + 6\right) + \left(y + 6\right)$

Taking common $y + 6$

Factors : $\left(y + 6\right) \left(4 y + 1\right)$