# How do you factor #4y^(2n)-4y^(n)-3#?

##### 1 Answer

Jan 26, 2016

#### Answer:

Treat as a quadratic in

#4y^(2n)-4y^n-3=(2y^n+1)(2y^n-3)#

#### Explanation:

Without knowing anything about

Find a pair of factors of

The pair

Use this pair to split the middle term and factor by grouping:

#4y^(2n)-4y^n-3#

#=4y^(2n)-6y^n+2y^n-3#

#=(4y^(2n)-6y^n)+(2y^n-3)#

#=2y^n(2y^n-3)+1(2y^n-3)#

#=(2y^n+1)(2y^n-3)#

If we knew more about