How do you factor #5z + 8yx + 4yz + 10x #?

1 Answer
Apr 6, 2016

Answer:

#(5+4y)(z+2x)#

Explanation:

Given
#color(white)("XXX")5z+8yx+4yz+10x#

Recognizing the #1:2# ratio of #5:10# and #4:8#
we can regroup the terms as
#color(white)("XXX")(5z+10x)+(4yz+8yx)#
then extract common factors from each pair of terms:
#color(white)("XXX")5(z+2x)+4y(z+2x)#

Recognize the common factor: #(z+2x)#
#color(white)("XXX")(5+4y)(z+2x)#