Question

How do you factor `64d ^ { 2} - 16d + 1`?

Answer 1

`(8d-1)^2`

Explanation:

`64d^2-16d+1 = (8d)^2 -16d +1^2`

Recall that:`(a-b)^2= a^2-2ab+b^2`

Hence, in our example: `a=8d` and `b=1`

Since: `2xx 8d xx 1 = 16d` the square is proved correct.

`->64d^2-16d+1 = (8d-1)^2`