Question

How do you factor `64m^3-5p`?

Answer 1

Have a look.

Explanation:

Given expression, `64m^3-5p`.

So, `64m^3-5p`
`=(4m)^3-(root(3)(5p))^3`
`=(4m-root(3)(5p))` `((4m)^2+4m.root(3)(5p)+(root(3)(5p))^2)`
`=(4m-root(3)(5p))(16m^2+4mroot(3)(5p)+(5p)^(2/3))`.

This is done by using the formula`rarr`
`(a-b)^3=(a-b)(a^2+ab+b^2)`.

Hope it Helps :)