How do you factor #64m^3-5p#?

1 Answer
Oct 7, 2017

Answer:

Have a look.

Explanation:

Given expression, #64m^3-5p#.

So, #64m^3-5p#
#=(4m)^3-(root(3)(5p))^3#
#=(4m-root(3)(5p))##((4m)^2+4m.root(3)(5p)+(root(3)(5p))^2)#
#=(4m-root(3)(5p))(16m^2+4mroot(3)(5p)+(5p)^(2/3))#.

This is done by using the formula#rarr#
#(a-b)^3=(a-b)(a^2+ab+b^2)#.

Hope it Helps :)