Question

How do you factor `64x ^ { 6} - 27d ^ { 9}`?

Answer 1

`(4x^2-3d^3)(16x^4+12x^2d^3+9d^6)`

Explanation:

`64x^6-27d^9 = (4x^2)^3-(3d^3)^3`

`[a^3 – b^3= (a – b) (a^2 + ab + b^2)].`

`:.(4x^2)^3-(3d^3)^3= (4x^2-3d^3)(16x^4+12x^2d^3+9d^6)`

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