# How do you factor #64y^3 - 125#?

##### 1 Answer

May 24, 2015

Use identity: a^3 - b^3 = (a - b)(a^2 + ab + b^2)

64y^3 - 125 = (4y - 5)(16y^2 + 20y + 25)

May 24, 2015

Use identity: a^3 - b^3 = (a - b)(a^2 + ab + b^2)

64y^3 - 125 = (4y - 5)(16y^2 + 20y + 25)

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