# How do you factor 6k^2h^4-54k^4?

Jun 30, 2017

$6 {k}^{2} \left({h}^{2} - 3 k\right) \left({h}^{2} + 3 k\right)$
Factor the $6 {k}^{2}$ out first:
$6 {k}^{2} \left({h}^{4} - 9 {k}^{2}\right)$