How do you factor #6p ^ { 2} + 8p - 5#?

1 Answer
EZ as pi
Jun 26, 2017

#6p^2+8p -5# does not have factors.

#6p^2+7p -5# does factor

Explanation:

#6p^2+8p -5# does not have factors.

There are no factors of 6 and 5 whose products differ by 8.

However #6p^2+7p -5# does factor.

#=(3p+5)(2p-1)#

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