# How do you factor 6p ^ { 4} - 24p ^ { 3} - 192p ^ { 2}?

May 14, 2017

$= 6 {p}^{2} \left(p - 8\right) \left(p + 4\right)$

#### Explanation:

$6 {p}^{4} - 24 {p}^{3} - 192 {p}^{2}$

$= 6 {p}^{2} \left({p}^{2} - 4 p - 32\right)$

$= 6 {p}^{2} \left({p}^{2} - 8 p + 4 p - 32\right)$

$= 6 {p}^{2} \left(p \left(p - 8\right) + 4 \left(p - 8\right)\right)$

$= 6 {p}^{2} \left(p - 8\right) \left(p + 4\right)$