# How do you factor -6x^2+6x^3 ?

$6 {x}^{2} \left(x - 1\right)$
First, you should try to 'pull out of the parentheses' as much as you can: in this case it's $6 {x}^{2}$. So we divide each monomial by $6 {x}^{2}$:
$- 6 {x}^{2} + 6 {x}^{3} = 6 {x}^{2} \left(- 1 + x\right)$,
We prefer the factors to be of the form $\left(x - \textrm{s o m e t h \in g}\right)$ so here we can just rearrange the last factor to obtain $6 {x}^{2} \left(x - 1\right)$.