Question

How do you factor `6x^2+7x-49`?

Answer 1

You can factor this by getting its roots, as follows (I'll use Bhaskara)

`(-7+-sqrt(49-4(6)(-49)))/12`
`(-7+-35)/12`
`x_1=-7/2`, which can be equaled to zero as the factor: `2x+7=0`
`x_2=7/3`, which can be equaled to zero as the factor: `3x-7=0`

Thus

`6x^2+7x-49=(2x+7)(3x-7)`