How do you factor 6z^2+12z-az-2a?

May 11, 2015

We can factor the expression by making groups of 2 terms:

$\left(6 {z}^{2} + 12 z\right) - \left(a z + 2 a\right)$

$6 z$ is a factor common to both the terms in the first group and
$a$ is a factor common to both the terms in the second group

We can write it as

$= 6 z \left(z + 2\right) - a \left(z + 2\right)$

$z + 2$ is common to both the terms in the expression

= color(green)((z+2)(6z-a)