How do you factor #7w ^ { 4} - 112# completely?

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Answer 1 · 2016-12-29T07:52:12

#7(w-2)(w+2)(w^2+4)#

First you can take out a common factor of 7.

#7(w^4-16)#

Then, since for difference of squares you can factor:

#a^2-b^2=(a-b)(a+b)#

the expression becomes:

#7(w^2-4)(w^2+4)#

and factor the difference of squares again:

#7(w-2)(w+2)(w^2+4)#