# How do you factor 8x^3-24x^2?

Notice that both of the terms are divisible by $8 {x}^{2}$, so separate that out to find:
$8 {x}^{3} - 24 {x}^{2} = 8 {x}^{2} \left(x - 3\right)$
Both $8 {x}^{3}$ and $24 {x}^{2}$ are divisible by $8 {x}^{2}$, so we find:
$8 {x}^{3} - 24 {x}^{2} = \left(8 {x}^{2} \cdot x\right) - \left(8 {x}^{2} \cdot 3\right) = 8 {x}^{2} \left(x - 3\right)$