How do you factor #8x^3-4x^2-2x+1#?

1 Answer
Mar 26, 2016

Answer:

#8x^3-4x^2-2x+1=(2x-1)(2x+1)(2x-1)#

Explanation:

Factor by grouping and using the difference of squares identity:

#a^2-b^2 = (a-b)(a+b)#

with #a=2x# and #b=1# as follows:

#8x^3-4x^2-2x+1#

#=(8x^3-4x^2)-(2x-1)#

#=4x^2(2x-1)-1(2x-1)#

#=(4x^2-1)(2x-1)#

#=((2x)^2-1^2)(2x-1)#

#=(2x-1)(2x+1)(2x-1)#