How do you factor #9x^2 - 36x + 36 = 0#?

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Answer 1 · 2017-02-10T14:26:43

#x=2#

In any factoring situation, always look for a common factor first, in this case, #HCF = 9#

As it is an equation rather than an expression, we can divide by 9.

#9x^2 -36x +36 =0" "larr div 9#

#x^2 -4x +4 = 0#

Find factors of 4 which add up to #4#
The signs in the brackets will be the same, both are minus.

#(x-2)(x-2)=0#

#x-2 = 0," "rarr x = 2#