How do you factor #a^6 + 1#?

1 Answer
Apr 14, 2015

We can modify the expression to use the Sum of Cubes formula to factorise it.

#a^6 + 1 = (a^2)^3 + 1^3#

The formula says :#color(blue)(x^3 + y^3 = (x + y)(x^2-xy+y^2)#

Here, #x# is #a^2# and #y# is #1#

#(a^2)^3 + 1^3 = (a^2+1){(a^2)^2 - (a^2*1)+1^2}#

#color(green)(= (a^2+1)(a^4 - a^2+1)#

As none of the factors can be factorised further, this becomes the Factorised form of #a^6 + 1#