How do you factor #ac + 2ad + 2bc + 4bd#?

2 Answers
Jun 30, 2015

Answer:

#(c+2d)(a+2b)#

Explanation:

In other factorize, we need to take out common factors.
We have here;
#ac+2ad+2bc+4bd#
Take out #a# as a common factor from first two variables and #2b# from last two variables, we get;
#=a(c+2d)+2b(c+2d)#
Now, again take out #(c+2d)# as a common factor, we get
#=(c+2d)(a+2b)#
This is our final answer.

Jun 30, 2015

Answer:

#ac+2ad+2bc+4bd#
#color(white)("XXXX")##=(a+2b)(c+2d)#

Explanation:

Given #ac+2ad+2bc+4bd#

Regroup as
#color(white)("XXXX")##color(red)((ac+2ad)) + color(blue)((2bc+4bd))#

Extract common factor from each term independently
#color(white)("XXXX")##color(red)((a)(c+2d)) + color(blue)((2b)(c+2d))#

Extract the factor common to both terms
#color(white)("XXXX")##(color(red)(a)+color(blue)(2b))(c+2d)#