How do you factor and simplify \frac { x ^ { 2} + 2x - 8} { x ^ { 2} - 9} \times \frac { x + 3} { x + 4}?

$\frac{x - 2}{x + 3}$
$\frac{{x}^{2} + 2 x - 8}{{x}^{2} - 9} \cdot \frac{x + 3}{x + 4}$
This factors out to $\frac{\cancel{\left(x + 4\right)} \left(x - 2\right)}{\left(x - 3\right) \cancel{\left(x + 3\right)}} \cdot \frac{\cancel{x + 3}}{\cancel{x + 4}}$
This simplifies to $\frac{x - 2}{x + 3}$