How do you factor and solve #2x^2+2x-2=0#?

1 Answer

Answer:

this equation cannot be solved by factorization that means it takes a lot of effort and time and hence we have to use the quadratic formula.

Explanation:

given equation #x^2+x-1=0#
first we have to check the nature of the roots by using discriminant
#D=b^2-4ac# substituting the values of #b=1,a=1,c=-1# we get
#D=1+4=5>0# hence we have real and distinct roots
applying the quadratic formula#color(red)[(-b+-sqrt(b^2-4ac))/(2a)]rArr[(-1+-sqrt(1+4))/2]rArr(-1+-sqrt5)/2#
hence the roots are #(-1+-sqrt5)/2#