How do you factor and solve #x^2 + 3x + 2 = 0#?

2 Answers
May 21, 2018

Answer:

#x=-2#

Explanation:

#x^2+3x+2=0#
#x^2+3x=0-2#

#x^2+3x=-2#

A squared number + #3x# = negative 2 (#-2#)

So #x# must be negative.

#-2^2+(3x-2)=-2#

#4+-6=-2#

#x=-2#

May 21, 2018

Answer:

#x=-2" or "x=-1#

Explanation:

#"the factors of + 2 which sum to + 3 are + 2 and + 1"#

#rArr(x+2)(x+1)=0#

#"equate each factor to zero and solve for x"#

#x+2=0rArrx=-2#

#x+1=0rArrx=-1#

#"solutions are "x=-2" or "x=-1#