# How do you factor and solve x^2-4x=3?

Apr 27, 2017

$x = 2 \pm \sqrt{7}$

#### Explanation:

${x}^{2} - 4 x = 3$

use completing a square or quadraric formulae to soive.
by using completing a square,
${\left(x - 2\right)}^{2} - {\left(- 2\right)}^{2} = 3$
${\left(x - 2\right)}^{2} = 3 + 4 = 7$
$\left(x - 2\right) = \pm \sqrt{7}$
$x = 2 \pm \sqrt{7}$

therefore it factor is
$\left(x - \left(2 + \sqrt{7}\right)\right) \left(x - \left(2 - \sqrt{7}\right)\right) = 0$