How do you factor $b^3 + 27$ ?

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Answer 1 · 2016-02-03T00:23:42

$b^3+27=(b+3)(b^2-3b+9)$

$b^3+27$ is an example of a sum of cubes, where $a=b$ and $b=3.$ . Rewrite the expression as $(b)^3+(3)^3$ .

To solve the sum of cubes, use the equation $a^3+b^3=(a+b)(a^2-ab+b^2)$ .

Substitute the values for $a and b$ into the equation.

$(b)^3+(3)^3=(b+3)(b^2-(b)(3)+3^2)$

Simplify.

$(b)^3+(3)^3=(b+3)(b^2-3b+9)$

How do you factor b^3 + 27b^3 + 27?