How do you factor by grouping #5n^2 + 19n + 12#?
Factor by grouping? This is just normal factoring, no grouping is needed:
If you want to use factoring by grouping anyway, then you have to break up the middle term with
When we do factoring by grouping, we want to split the
Notice, the blue terms are equivalent, so I didn't change the meaning of this expression.
Now, we can factor!
We can factor a
which can be rewritten as
Hope this helps!
Use an AC method to split the middle term, then factor by grouping to find:
#5n^2+19n+12 = (5n+4)(n+3)#
Use an AC Method to find the split we need.
Look for a pair of factors of
Using this pair to split the middle term, we can then factor by grouping:
#5n^2+19n+12 = (5n^2+15n)+(4n+12)#
#color(white)(5n^2+19n+12) = 5n(n+3)+4(n+3)#
#color(white)(5n^2+19n+12) = (5n+4)(n+3)#