How do you factor by grouping #5n^2 + 19n + 12#?
3 Answers
Explanation:
Factor by grouping? This is just normal factoring, no grouping is needed:
If you want to use factoring by grouping anyway, then you have to break up the middle term with
Explanation:
When we do factoring by grouping, we want to split the
Notice, the blue terms are equivalent, so I didn't change the meaning of this expression.
Now, we can factor!
We can factor a
which can be rewritten as
Hope this helps!
Use an AC method to split the middle term, then factor by grouping to find:
#5n^2+19n+12 = (5n+4)(n+3)#
Explanation:
Given:
#5n^2+19n+12#
Use an AC Method to find the split we need.
Look for a pair of factors of
The pair
Using this pair to split the middle term, we can then factor by grouping:
#5n^2+19n+12 = (5n^2+15n)+(4n+12)#
#color(white)(5n^2+19n+12) = 5n(n+3)+4(n+3)#
#color(white)(5n^2+19n+12) = (5n+4)(n+3)#