# How do you factor by grouping #5n^2 + 19n + 12#?

##### 3 Answers

#### Explanation:

Factor by grouping? This is just normal factoring, no grouping is needed:

If you want to use factoring by grouping anyway, then you have to break up the middle term with

#### Explanation:

When we do factoring by grouping, we want to split the

Notice, the blue terms are equivalent, so I didn't change the meaning of this expression.

Now, we can factor!

We can factor a

which can be rewritten as

Hope this helps!

Use an AC method to split the middle term, then factor by grouping to find:

#5n^2+19n+12 = (5n+4)(n+3)#

#### Explanation:

Given:

#5n^2+19n+12#

Use an AC Method to find the split we need.

Look for a pair of factors of

The pair

Using this pair to split the middle term, we can then factor by grouping:

#5n^2+19n+12 = (5n^2+15n)+(4n+12)#

#color(white)(5n^2+19n+12) = 5n(n+3)+4(n+3)#

#color(white)(5n^2+19n+12) = (5n+4)(n+3)#