How do you factor by grouping #xy+4x-2y-8#? Algebra Polynomials and Factoring Factoring by Grouping 1 Answer GiĆ³ Apr 15, 2015 Try collecting #y# between the first and third term and #4# between the second and the fourth: #y(x-2)+4(x-2)=# now collect #(x-2)#; #(x-2)(y+4)# Answer link Related questions What is Factoring by Grouping? How do you factor by grouping four-term polynomials and trinomials? Why does factoring polynomials by grouping work? How do you factor #2x+2y+ax+ay#? How do you factor #3x^2+8x+4# by using the grouping method? How do you factor #6x^2-9x+10x-15#? How do you group and factor #4jk-8j^2+5k-10j#? What are the factors of #2m^3+3m^2+4m+6#? How do you factor quadratics by using the grouping method? How do you factor #x^4-2x^3+5x-10#? See all questions in Factoring by Grouping Impact of this question 3774 views around the world You can reuse this answer Creative Commons License