How do you factor #c^2 + 7c +6#?

2 Answers
smendyka
May 27, 2017

Play with various factors for #6# which also add up to #7# to factor this expression as:

#(c + 6)(c + 1)#

Jim G.
May 27, 2017

#(c+1)(c+6)#

Explanation:

#"factorise by 'splitting' the middle term"#

#rArrc^2+7c+6#

#=c^2+c+6c+6to7c=c+6c#

#"factorise by grouping"#

#=color(red)(c)(c+1)color(red)(+6)(c+1)#

#"take out the common factor "(c+1)#

#=(c+1)(color(red)(c+6))#

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