How do you factor #c^2+c-12#?

1 Answer
EZ as pi
Sep 12, 2016

#(c+4)(c-3)#

Explanation:

#c^2 +1c-12 " "larr# a quadratic trinomial

Find the factors of 12 which SUBTRACT (because of (MINUS 12)
to give 1 (because of 1c)

#3xx4 = 12" " and " "4-3 = 1" "larr# the factors are 4 and 3

The signs will be DIFFERENT (because of MINUS 12), there must be more POSITIVE (because of PLUS 1)

#(c+4)(c-3)#

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