# How do you factor completely: 16x^2 – 9?

Jul 11, 2015

$16 {x}^{2} - 9 = \left(4 x + 3\right) \left(4 x - 3\right)$

#### Explanation:

$16 {x}^{2} - 9$

This is an example of the difference of squares, in which ${a}^{2} - {b}^{2} = \left(a + b\right) \left(a - b\right)$.

$a = 4 x ,$ $b = 3$

$16 {x}^{2} - 9 = \left(4 x + 3\right) \left(4 x - 3\right)$