# How do you factor completely 2x^2 - 20x - 48?

Apr 15, 2016

$2 \left({x}^{2} - 10 x - 24\right)$
$= 2 \left({x}^{2} - 12 x + 2 x - 24\right)$
=2(x(x-12)+2(x-12)
$= 2 \left(x - 12\right) \left(x + 2\right)$

Apr 15, 2016

y = 2(x +2)(x - 12)

#### Explanation:

$y = 2 \left({x}^{2} - 10 x - 24\right)$.
Next, factor the trinomial in parentheses.
Find 2 numbers knowing sum (-10) and product (-24).
Factor pairs of (-24) --> (-2, 12)(2, -12). This sum is (-10 = b).
The 2 numbers are: 2 and - 12.
y = 2(x + 2)(x - 12)