Question

How do you factor completely `2x^2 - 20x - 48`?

Answer 1

`2(x^2-10x-24)`
`=2(x^2-12x+2x-24)`
`=2(x(x-12)+2(x-12)`
`=2(x-12)(x+2)`

Answer 2

y = 2(x +2)(x - 12)

Explanation:

`y = 2(x^2 - 10x - 24)`.
Next, factor the trinomial in parentheses.
Find 2 numbers knowing sum (-10) and product (-24).
Factor pairs of (-24) --> (-2, 12)(2, -12). This sum is (-10 = b).
The 2 numbers are: 2 and - 12.
y = 2(x + 2)(x - 12)