How do you factor completely #2x^2 - 20x - 48#?

2 Answers
Apr 15, 2016

#2(x^2-10x-24)#
#=2(x^2-12x+2x-24)#
#=2(x(x-12)+2(x-12)#
#=2(x-12)(x+2)#

Apr 15, 2016

Answer:

y = 2(x +2)(x - 12)

Explanation:

#y = 2(x^2 - 10x - 24)#.
Next, factor the trinomial in parentheses.
Find 2 numbers knowing sum (-10) and product (-24).
Factor pairs of (-24) --> (-2, 12)(2, -12). This sum is (-10 = b).
The 2 numbers are: 2 and - 12.
y = 2(x + 2)(x - 12)