How do you factor completely # 2x^2 + 8x + 8#?

2 Answers
May 19, 2018

Answer:

#2(x+2)^2#

Explanation:

#2x^2+8x+8# has a GCF 2 so factor that out first

#2(x^2+4x +4)#

now factor:

#2(x+2)(x+2)#

finally:

#2(x+2)^2#

May 19, 2018

Answer:

#color(indigo)(=> 2 * (x + 2)^2#

Explanation:

Given : #2x^2 + 8x + 8#

#=> 2 (x^2 + 4x + 4)#

#=> 2(x^2 + 2x + 2x + 4)#

#=>2 (x (x + 2) + 2 (x+ 2))#

#=> 2 * (x+2) * (x+2)#

#color(indigo)(=> 2 (x + 2)^2#