How do you factor completely # 2x^2 + 8x + 8#?

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Answer 1 · 2018-05-19T03:38:08

#2(x+2)^2#

#2x^2+8x+8# has a GCF 2 so factor that out first

#2(x^2+4x +4)#

now factor:

#2(x+2)(x+2)#

finally:

#2(x+2)^2#

Answer 2 · 2018-05-19T03:40:24

#color(indigo)(=> 2 * (x + 2)^2#

Given : #2x^2 + 8x + 8#

#=> 2 (x^2 + 4x + 4)#

#=> 2(x^2 + 2x + 2x + 4)#

#=>2 (x (x + 2) + 2 (x+ 2))#

#=> 2 * (x+2) * (x+2)#

#color(indigo)(=> 2 (x + 2)^2#