# How do you factor f(x)=x^3-2x^2+3 ?

$\left(x + 1\right) \left({x}^{2} - 3 x + 3\right)$
For x=-1, f(-1)=0 , hence x+1 is a factor of f(x). Now divide f(x) by x+1, synthetic or long division, the quotient would come out to be ${x}^{2} - 3 x + 3$. The factors of f(x) are $\left(x + 1\right) \left({x}^{2} - 3 x + 3\right)$