How do you factor #h^2-12h+27#?

1 Answer
Nov 14, 2015

Answer:

# h = 9 , 3#

Explanation:

Factor the first expression. # h^2 -> h , h#
Factor the last expression. # 27 -> 3 , 9#
Since the last expression is positive, and the second expression is negative, BOTH of the factors must be negative.
# (h - 3) , (h - 9) =0#
To make this true, the first factor could be equal to zero, or the second factor could be zero.
#(h-3)=0 -> h=3# or #(h-9)=0 ->h=9#