# How do you factor h^2-12h+27?

Nov 14, 2015

$h = 9 , 3$

#### Explanation:

Factor the first expression. ${h}^{2} \to h , h$
Factor the last expression. $27 \to 3 , 9$
Since the last expression is positive, and the second expression is negative, BOTH of the factors must be negative.
$\left(h - 3\right) , \left(h - 9\right) = 0$
To make this true, the first factor could be equal to zero, or the second factor could be zero.
$\left(h - 3\right) = 0 \to h = 3$ or $\left(h - 9\right) = 0 \to h = 9$