# How do you factor h^2-12h+27?

Nov 14, 2015

$h = 9 , 3$
Factor the first expression. ${h}^{2} \to h , h$
Factor the last expression. $27 \to 3 , 9$
$\left(h - 3\right) , \left(h - 9\right) = 0$
$\left(h - 3\right) = 0 \to h = 3$ or $\left(h - 9\right) = 0 \to h = 9$