How do you factor out the coefficient of the variable given #2b+8#?
1 Answer
Dec 2, 2016
See below
Explanation:
This is hypothetical as I am not clear on what exactly the question gives you.
Version one: equation is equal to 0
- Given equation
#2b+8# that equals zero,#2b+8=0# - Isolate the 2b by subtracting 8 from each side
#2b\cancel(+8)\cancel(\color(red)(-8))=0\color(red)(-8)\rarr2b=-8# - Divide both sides by 2 to isolate b
#(\cancel(2b) )/(\cancel(\color(seagreen)(2)))=(-8)/(\color(seagreen)(2))\rarrb=-8\div2=-4#
Version two: no quantity equivalence
- GIven function
#2b+8# we can apply the Distributive Property - convert to proper form
#2b+8\rArr2(b)+2(z)# where#2z=8# - To get variable
#z\rArr8\div2=z=4# , therefore you have#2(b)+2(4)# or in factored form,#2(b+4)#
