# How do you factor out the coefficient of the variable given 2b+8?

Dec 2, 2016

See below

#### Explanation:

This is hypothetical as I am not clear on what exactly the question gives you.

Version one: equation is equal to 0

• Given equation $2 b + 8$ that equals zero, $2 b + 8 = 0$
• Isolate the 2b by subtracting 8 from each side $2 b \setminus \cancel{+ 8} \setminus \cancel{\setminus \textcolor{red}{- 8}} = 0 \setminus \textcolor{red}{- 8} \setminus \rightarrow 2 b = - 8$
• Divide both sides by 2 to isolate b (\cancel(2b) )/(\cancel(\color(seagreen)(2)))=(-8)/(\color(seagreen)(2))\rarrb=-8\div2=-4

Version two: no quantity equivalence

• GIven function $2 b + 8$ we can apply the Distributive Property
• convert to proper form $2 b + 8 \setminus \Rightarrow 2 \left(b\right) + 2 \left(z\right)$ where $2 z = 8$
• To get variable $z \setminus \Rightarrow 8 \setminus \div 2 = z = 4$, therefore you have $2 \left(b\right) + 2 \left(4\right)$ or in factored form, $2 \left(b + 4\right)$