How do you factor out the coefficient of the variable given #2b+8#?

1 Answer
Dec 2, 2016

Answer:

See below

Explanation:

This is hypothetical as I am not clear on what exactly the question gives you.


Version one: equation is equal to 0

  • Given equation #2b+8# that equals zero, #2b+8=0#
  • Isolate the 2b by subtracting 8 from each side #2b\cancel(+8)\cancel(\color(red)(-8))=0\color(red)(-8)\rarr2b=-8#
  • Divide both sides by 2 to isolate b #(\cancel(2b) )/(\cancel(\color(seagreen)(2)))=(-8)/(\color(seagreen)(2))\rarrb=-8\div2=-4#

Version two: no quantity equivalence

  • GIven function #2b+8# we can apply the Distributive Property
  • convert to proper form #2b+8\rArr2(b)+2(z)# where #2z=8#
  • To get variable #z\rArr8\div2=z=4#, therefore you have #2(b)+2(4)# or in factored form, #2(b+4)#