How do you factor out the coefficient of the variable given 2b+8?
1 Answer
Dec 2, 2016
See below
Explanation:
This is hypothetical as I am not clear on what exactly the question gives you.
Version one: equation is equal to 0
- Given equation
2b+8 that equals zero,2b+8=0 - Isolate the 2b by subtracting 8 from each side
2b\cancel(+8)\cancel(\color(red)(-8))=0\color(red)(-8)\rarr2b=-8 - Divide both sides by 2 to isolate b
(\cancel(2b) )/(\cancel(\color(seagreen)(2)))=(-8)/(\color(seagreen)(2))\rarrb=-8\div2=-4
Version two: no quantity equivalence
- GIven function
2b+8 we can apply the Distributive Property - convert to proper form
2b+8\rArr2(b)+2(z) where2z=8 - To get variable
z\rArr8\div2=z=4 , therefore you have2(b)+2(4) or in factored form,2(b+4)