# How do you factor out the coefficient of the variable given #2b+8#?

##### 1 Answer

Dec 2, 2016

See below

#### Explanation:

**This is hypothetical as I am not clear on what exactly the question gives you.**

**Version one: equation is equal to 0**

*Given equation*#2b+8# *that equals zero,*#2b+8=0# *Isolate the 2b by subtracting 8 from each side*#2b\cancel(+8)\cancel(\color(red)(-8))=0\color(red)(-8)\rarr2b=-8# *Divide both sides by 2 to isolate b*#(\cancel(2b) )/(\cancel(\color(seagreen)(2)))=(-8)/(\color(seagreen)(2))\rarrb=-8\div2=-4#

**Version two: no quantity equivalence**

*GIven function*#2b+8# *we can apply the Distributive Property**convert to proper form*#2b+8\rArr2(b)+2(z)# where#2z=8# *To get variable*#z\rArr8\div2=z=4# ,*therefore you have*#2(b)+2(4)# *or in factored form,*#2(b+4)#