How do you factor #r^ { 4} - 5r ^ { 3} + 4r ^ { 2}#?

1 Answer
Jul 15, 2017

See a solution process below:

Explanation:

First, factor out an #r^2# from each term:

#(r^2 * r^2) - (r^2 * 5r) + (r^2 * 4) =>#

#r^2(r^2 - 5r + 4)#

Now, factor the expression within the parenthesis as:

#r^2(r - 4)(r - 1)#