# How do you factor  s^3 + s^2 +4sq^2 + 4q^2?

Apr 8, 2016

$\left(s + 1\right) \left({s}^{2} + 4 {q}^{2}\right)$

#### Explanation:

Group the terms into 'pairs' as follows.

$\left[{s}^{3} + {s}^{2}\right] + \left[4 s {q}^{2} + 4 {q}^{2}\right]$

now factorise each pair.

$\Rightarrow {s}^{2} \left(s + 1\right) + 4 {q}^{2} \left(s + 1\right)$

We can now take out a common factor of (s + 1 )

$\Rightarrow \left(s + 1\right) \left({s}^{2} + 4 {q}^{2}\right)$