How do you factor #t^2 - 2tz - 80z^2#?

1 Answer
EZ as pi
Apr 15, 2018

#(t+8z)(t-10z)#

Explanation:

Find two factors of #80# which differ by #2#

They will be #8 and 10#

#8 xx 10 = 80 and 10-8=2#

#(t+8z)(t-10z)#

When these are multiplied, the middle terms will be #+8z and -10z# which will give the required term of #-2z#

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