How do you factor #t^2-5t+6#?

2 Answers
hev1
Apr 8, 2018

#t^2 - 5t +6 = (t-2)(t-3)#

Explanation:

In a trinomial with the degree #2# and with #1# as the leading coefficient, you need to find two numbers that add up to the second term and have a product that is the third term.

In this trinomial, the sum (second term) is #-5# and the product (third term) is #6#.
The numbers #-2# and #-3# satisfy the terms.
Therefore, #t^2 - 5t +6 = (t-2)(t-3)#.

Jim G.
Apr 8, 2018

#(t-2)(t-3)#

Explanation:

#"the factors of + 6 which sum to - 5 are - 2 and - 3"#

#rArrt^2-5t+6=(t-2)(t-3)#

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