# How do you factor the expression -14x+8+6x^2?

Jul 19, 2016

2(x - 1)(3x - 4)

#### Explanation:

Bring the expression to standard form:
$f \left(x\right) = 6 {x}^{2} - 14 x + 8$
Since a + b + c = 0
- One real root is (1) and the factor is (x - 1)
- One real root is $\left(\frac{c}{a} = \frac{8}{6}\right)$ and the factor is $\left(x - \frac{8}{6}\right)$
Factor form of f(x):
$f \left(x\right) = a \left(x - x 1\right) \left(x - x 2\right) = 6 \left(x - 1\right) \left(x - \frac{8}{6}\right) = \left(x - 1\right) \left(6 x - 8\right) = 2 \left(x - 1\right) \left(3 x - 4\right)$