# How do you factor the monomial 121abc^3 completely?

May 19, 2017

$121 a b {c}^{2} = 11 \times 11 \times a \times b \times c \times c$

#### Explanation:

We know that $121 a b {c}^{3}$ is nothing but $121 \times a \times b \times {c}^{2}$

i.e. $121 \times a \times b \times c \times c$

Hence to factor given monomial, one just needs to factorize $121$ and as $121 = 11 \times 11$

$121 a b {c}^{2} = 11 \times 11 \times a \times b \times c \times c$